Dielectric Breakdown - Revision history

Lwcamp at 18:59, 7 March 2026

2026-03-07T18:59:42Z

← Older revision		Revision as of 11:59, 7 March 2026
Line 31:		Line 31:
	==References==		==References==

	[[Category:Lasers]][[Category:Physics & Engineering]]		[[Category:Lasers]][[Category:Physics & Engineering]][[Category:Physics & Math & Engineering]]

Lwcamp at 13:38, 27 May 2025

2025-05-27T13:38:35Z

← Older revision		Revision as of 06:38, 27 May 2025
Line 10:		Line 10:
	<ref name=Radziemski_1989>Leon J. Radziemski and David A. Cremers, Ed., "Laser-Induced Plasmas and Applications", Marcel Dekker, New York, 1989.</ref>		<ref name=Radziemski_1989>Leon J. Radziemski and David A. Cremers, Ed., "Laser-Induced Plasmas and Applications", Marcel Dekker, New York, 1989.</ref>
	<ref name=Ali_1983>A. W. Ali, “On Laser Air Breakdown, Threshold Power and Laser Generated Channel Length”, NRL Memorandum Report 5187 AD-A133 2.11, September 13, 1983.</ref>		<ref name=Ali_1983>A. W. Ali, “On Laser Air Breakdown, Threshold Power and Laser Generated Channel Length”, NRL Memorandum Report 5187 AD-A133 2.11, September 13, 1983.</ref>
	Find the threshold intensity <math>I_{Th}</math> in watts per square ~~centimeters~~		Find the threshold intensity <math>I_{Th}</math> in watts per square centimeter
	<div class="center" style="width: auto; margin-left: auto; margin-right: auto;"><math>		<div class="center" style="width: auto; margin-left: auto; margin-right: auto;"><math>
	\begin{array}{lll}		\begin{array}{lll}

Lwcamp at 13:38, 27 May 2025

2025-05-27T13:38:24Z

← Older revision		Revision as of 06:38, 27 May 2025
Line 10:		Line 10:
	<ref name=Radziemski_1989>Leon J. Radziemski and David A. Cremers, Ed., "Laser-Induced Plasmas and Applications", Marcel Dekker, New York, 1989.</ref>		<ref name=Radziemski_1989>Leon J. Radziemski and David A. Cremers, Ed., "Laser-Induced Plasmas and Applications", Marcel Dekker, New York, 1989.</ref>
	<ref name=Ali_1983>A. W. Ali, “On Laser Air Breakdown, Threshold Power and Laser Generated Channel Length”, NRL Memorandum Report 5187 AD-A133 2.11, September 13, 1983.</ref>		<ref name=Ali_1983>A. W. Ali, “On Laser Air Breakdown, Threshold Power and Laser Generated Channel Length”, NRL Memorandum Report 5187 AD-A133 2.11, September 13, 1983.</ref>
	Find the threshold intensity <math>I_{Th}</math>		Find the threshold intensity <math>I_{Th}</math> in watts per square centimeters
	<div class="center" style="width: auto; margin-left: auto; margin-right: auto;"><math>		<div class="center" style="width: auto; margin-left: auto; margin-right: auto;"><math>
	\begin{array}{lll}		\begin{array}{lll}

Tshhmon at 21:30, 23 April 2024

2024-04-23T21:30:12Z

← Older revision		Revision as of 14:30, 23 April 2024
Line 31:		Line 31:
	==References==		==References==

	[[Category:Lasers]]		[[Category:Lasers]][[Category:Physics & Engineering]]

Lwcamp at 22:22, 12 January 2022

2022-01-12T22:22:09Z

← Older revision		Revision as of 15:22, 12 January 2022
Line 5:		Line 5:
	Second, light is a wave, and it has a frequency. This means the electric field periodically turns around and pulls the electrons the other way. All that energy they’d been getting from the field is now being drained away. If the laser light’s frequency is high enough, the electrons just jiggle up and down slightly without ever getting enough energy to start the breakdown process.		Second, light is a wave, and it has a frequency. This means the electric field periodically turns around and pulls the electrons the other way. All that energy they’d been getting from the field is now being drained away. If the laser light’s frequency is high enough, the electrons just jiggle up and down slightly without ever getting enough energy to start the breakdown process.

	As you might have guessed by now, this process is not good if it happens part-way along your beam when you are trying to shoot a bad guy. Ripping off all those electrons takes a lot of energy, energy that comes from your beam! Not only that, but plasma is hot, low density, and has funky electrical properties that turn it into a lens. The light it doesn’t absorb gets scattered out of your beam and away from your target. And finally, if the wavelength of your beam is longer than somewhere between 5 and 2 μm (65 to 150 THz ~~or0~~.3 to 0.7 eV, in sea level density air and depending on how much ionization occurs), the plasma just directly absorbs your beam, using your beam’s energy to heat itself up even more so it can absorb and scatter your beam further. Not nice, plasma! Are you working for my target, perhaps?		As you might have guessed by now, this process is not good if it happens part-way along your beam when you are trying to shoot a bad guy. Ripping off all those electrons takes a lot of energy, energy that comes from your beam! Not only that, but plasma is hot, low density, and has funky electrical properties that turn it into a lens. The light it doesn’t absorb gets scattered out of your beam and away from your target. And finally, if the wavelength of your beam is longer than somewhere between 5 and 2 μm (65 to 150 THz or 0.3 to 0.7 eV, in sea level density air and depending on how much ionization occurs), the plasma just directly absorbs your beam, using your beam’s energy to heat itself up even more so it can absorb and scatter your beam further. Not nice, plasma! Are you working for my target, perhaps?

	But will your design for a laser beam death annihilation ray suffer from breakdown? Here’s a way to get a quick estimate.		But will your design for a laser beam death annihilation ray suffer from breakdown? Here’s a way to get a quick estimate.

Lwcamp at 05:00, 12 October 2021

2021-10-12T05:00:55Z

← Older revision		Revision as of 22:00, 11 October 2021
Line 25:		Line 25:

	A curious effect can occur if you start dielectric breakdown. The plasma spark initially grows by absorbing beam energy and conducting that energy to the surrounding air. But once it is big enough, the plasma can shield its back part from the incoming laser while the front region continues to be heated and grow. The result? You launch a wave of plasma back down the beam toward the laser emitter! For focused beams, this plasma wave can only go so far as the beam is still focused enough to sustain the plasma, so you don't risk blowing yourself up when you shoot.		A curious effect can occur if you start dielectric breakdown. The plasma spark initially grows by absorbing beam energy and conducting that energy to the surrounding air. But once it is big enough, the plasma can shield its back part from the incoming laser while the front region continues to be heated and grow. The result? You launch a wave of plasma back down the beam toward the laser emitter! For focused beams, this plasma wave can only go so far as the beam is still focused enough to sustain the plasma, so you don't risk blowing yourself up when you shoot.

			==Credit==
			Author: Luke Campbell

			==References==

	[[Category:Lasers]]		[[Category:Lasers]]

Lwcamp at 15:36, 29 September 2021

2021-09-29T15:36:35Z

← Older revision		Revision as of 08:36, 29 September 2021
Line 23:		Line 23:
	</math></div>		</math></div>
	is close to <math>I_{Th}</math>, there’s a risk you’ll start a cascade breakdown, If it is much larger than <math>I_{Th}</math>, you will almost certainly cause an air breakdown. If it is much less, you’re safe. Go ahead and blaze away!		is close to <math>I_{Th}</math>, there’s a risk you’ll start a cascade breakdown, If it is much larger than <math>I_{Th}</math>, you will almost certainly cause an air breakdown. If it is much less, you’re safe. Go ahead and blaze away!

			A curious effect can occur if you start dielectric breakdown. The plasma spark initially grows by absorbing beam energy and conducting that energy to the surrounding air. But once it is big enough, the plasma can shield its back part from the incoming laser while the front region continues to be heated and grow. The result? You launch a wave of plasma back down the beam toward the laser emitter! For focused beams, this plasma wave can only go so far as the beam is still focused enough to sustain the plasma, so you don't risk blowing yourself up when you shoot.

	[[Category:Lasers]]		[[Category:Lasers]]

Lwcamp at 15:18, 29 September 2021

2021-09-29T15:18:01Z

← Older revision		Revision as of 08:18, 29 September 2021
Line 23:		Line 23:
	</math></div>		</math></div>
	is close to <math>I_{Th}</math>, there’s a risk you’ll start a cascade breakdown, If it is much larger than <math>I_{Th}</math>, you will almost certainly cause an air breakdown. If it is much less, you’re safe. Go ahead and blaze away!		is close to <math>I_{Th}</math>, there’s a risk you’ll start a cascade breakdown, If it is much larger than <math>I_{Th}</math>, you will almost certainly cause an air breakdown. If it is much less, you’re safe. Go ahead and blaze away!

			[[Category:Lasers]]

Lwcamp: Created page with "An electron is happily mining its own business floating freely around in the air when suddenly a high power laser beam comes by. How rude! The electric field of the laser be..."

2021-09-29T05:09:57Z

Created page with "An electron is happily mining its own business floating freely around in the air when suddenly a high power laser beam comes by. How rude! The electric field of the laser be..."

New page

An electron is happily mining its own business floating freely around in the air when suddenly a high power laser beam comes by. How rude! The electric field of the laser beam starts tugging on the electric charge of the electron, accelerating it to faster and faster speeds. Soon, the electron has more than enough energy to knock out other electrons that are stuck on to atoms. Now the electric field starts tugging on these newly freed electrons, too, and they start knocking off more free electrons of their own. Soon, you get a runaway process where the air turns into an electron soup. This electron soup is called a plasma, and the air has just experienced dielectric breakdown.

You need to get a couple things right in order to get dielectric breakdown. First, if the electrons bump into air molecules before they gain enough energy to knock out additional electrons, then they just get scattered in random directions and need to be re-accelerated by the field. So too dense of air or not strong enough laser light means free electrons just bounce off air molecules without ever starting the breakdown cascade.

Second, light is a wave, and it has a frequency. This means the electric field periodically turns around and pulls the electrons the other way. All that energy they’d been getting from the field is now being drained away. If the laser light’s frequency is high enough, the electrons just jiggle up and down slightly without ever getting enough energy to start the breakdown process.

As you might have guessed by now, this process is not good if it happens part-way along your beam when you are trying to shoot a bad guy. Ripping off all those electrons takes a lot of energy, energy that comes from your beam! Not only that, but plasma is hot, low density, and has funky electrical properties that turn it into a lens. The light it doesn’t absorb gets scattered out of your beam and away from your target. And finally, if the wavelength of your beam is longer than somewhere between 5 and 2 μm (65 to 150 THz or0.3 to 0.7 eV, in sea level density air and depending on how much ionization occurs), the plasma just directly absorbs your beam, using your beam’s energy to heat itself up even more so it can absorb and scatter your beam further. Not nice, plasma! Are you working for my target, perhaps?

But will your design for a laser beam death annihilation ray suffer from breakdown? Here’s a way to get a quick estimate.
<ref name=Radziemski_1989>Leon J. Radziemski and David A. Cremers, Ed., "Laser-Induced Plasmas and Applications", Marcel Dekker, New York, 1989.</ref>
<ref name=Ali_1983>A. W. Ali, “On Laser Air Breakdown, Threshold Power and Laser Generated Channel Length”, NRL Memorandum Report 5187 AD-A133 2.11, September 13, 1983.</ref>
Find the threshold intensity <math>I_{Th}</math>
<div class="center" style="width: auto; margin-left: auto; margin-right: auto;"><math>
\begin{array}{lll}
I_{Th,CW} & = & 0.31 \left[ \dfrac{1 \, \mbox{m}}{\lambda} \, \left( \dfrac{10^5 \, \mbox{Pa}}{p} \right)^{0.6} \right]^2 \\
I_{Th,pulse} & = & 6.35 \times 10^{-5} \left[ \left( \dfrac{1 \, \mbox{m}}{\lambda} \right)^2 \, \left( \dfrac{10^5 \, \mbox{Pa s}}{p \, t} \right)^{0.6} \right]
\end{array}
</math></div>
where <math>P</math> is the beam power, <math>E</math> is the beam energy, <math>t</math> is the beam duration, <math>p</math> is the air pressure, and <math>\lambda</math> is the beam wavelength;
and take <math>I_{Th}</math> as the larger of these two. If
<div class="center" style="width: auto; margin-left: auto; margin-right: auto;"><math>
I = \frac{4 \, P}{S^2} = \frac{4 \, E}{t S^2}
</math></div>
is close to <math>I_{Th}</math>, there’s a risk you’ll start a cascade breakdown, If it is much larger than <math>I_{Th}</math>, you will almost certainly cause an air breakdown. If it is much less, you’re safe. Go ahead and blaze away!